45y^2+36y+7=0

Solution for 45y^2+36y+7=0 equation:

45y^2+36y+7=0

a = 45; b = 36; c = +7;
Δ = b2-4ac
Δ = 362-4·45·7
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-6}{2*45}=\frac{-42}{90}
=-7/15
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+6}{2*45}=\frac{-30}{90}
=-1/3
$